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11.5E：练习
https://query.libretexts.org/%E7%AE%80%E4%BD%93%E4%B8%AD%E6%96%87/%E4%B8%AD%E7%BA%A7%E4%BB%A3%E6%95%B0_(OpenStax)/11%3A_Conics/11.05%3A_%E5%8F%8C%E6%9B%B2%E7%BA%BF/11.5E%3A_11.5E%EF%BC%9A%E7%BB%83%E4%B9%A0
$\frac{(y+4)^{2}}{25}-\frac{(x+1)^{2}}{36}=1$ $\frac{(y+1)^{2}}{16}-\frac{(x+1)^{2}}{4}=1$ $\frac{(y-4)^{2}}{16}-\frac{(x+1)^{2}}{25}=1$ $\frac{(x+2)^{2}}{4}-\frac{(y-1)^{2}}{9}=1$ \(9 x^{2}-4... $\frac{(y+4)^{2}}{25}-\frac{(x+1)^{2}}{36}=1$ $\frac{(y+1)^{2}}{16}-\frac{(x+1)^{2}}{4}=1$ $\frac{(y-4)^{2}}{16}-\frac{(x+1)^{2}}{25}=1$ $\frac{(x+2)^{2}}{4}-\frac{(y-1)^{2}}{9}=1$ $9 x^{2}-4 y^{2}-18 x+8 y-31=0$ $y^{2}-x^{2}-4 y+2 x-6=0$ $4 y^{2}-16 x^{2}-24 y+96 x-172=0$ $\frac{(y+1)^{2}}{1}-\frac{(x+2)^{2}}{9}=1$ $\frac{(y-3)^{2}}{9}-\frac{(x+2)^{2}}{16}=1$ $x^{2}+y^{2}-4 x+10 y-7=0$ $9 x^{2}-4 y^{2}+54 x+8 y+41=0$ $x=-y^{2}-2 y+3$
11.5E: تمارين
https://query.libretexts.org/%D8%A7%D9%84%D9%84%D8%BA%D8%A9_%D8%A7%D9%84%D8%B9%D8%B1%D8%A8%D9%8A%D8%A9/%D8%A7%D9%84%D8%AC%D8%A8%D8%B1_%D8%A7%D9%84%D9%85%D8%AA%D9%88%D8%B3%D8%B7_(OpenStax)/11%3A_%D8%A7%D9%84%D9%82%D8%B5%D8%B5_%D8%A7%D9%84%D9%85%D8%B5%D9%88%D8%B1%D8%A9/11.05%3A_%D8%A7%D9%84%D8%BA%D9%84%D9%88/11.5E%3A_%D8%AA%D9%85%D8%A7%D8%B1%D9%8A%D9%86
$\frac{(y+4)^{2}}{25}-\frac{(x+1)^{2}}{36}=1$ $\frac{(y+1)^{2}}{16}-\frac{(x+1)^{2}}{4}=1$ $\frac{(y-4)^{2}}{16}-\frac{(x+1)^{2}}{25}=1$ $\frac{(x+2)^{2}}{4}-\frac{(y-1)^{2}}{9}=1$ \(9 x^{2}-4... $\frac{(y+4)^{2}}{25}-\frac{(x+1)^{2}}{36}=1$ $\frac{(y+1)^{2}}{16}-\frac{(x+1)^{2}}{4}=1$ $\frac{(y-4)^{2}}{16}-\frac{(x+1)^{2}}{25}=1$ $\frac{(x+2)^{2}}{4}-\frac{(y-1)^{2}}{9}=1$ $9 x^{2}-4 y^{2}-18 x+8 y-31=0$ $y^{2}-x^{2}-4 y+2 x-6=0$ $4 y^{2}-16 x^{2}-24 y+96 x-172=0$ $\frac{(y+1)^{2}}{1}-\frac{(x+2)^{2}}{9}=1$ $\frac{(y-3)^{2}}{9}-\frac{(x+2)^{2}}{16}=1$ $x^{2}+y^{2}-4 x+10 y-7=0$ $9 x^{2}-4 y^{2}+54 x+8 y+41=0$ $x=-y^{2}-2 y+3$
11.5E : Exercices
https://query.libretexts.org/Francais/Alg%C3%A8bre_interm%C3%A9diaire_(OpenStax)/11%3A_Bandes_dessin%C3%A9es/11.05%3A_Hyperboles/11.5E%3A_Exercices
$\frac{(y+4)^{2}}{25}-\frac{(x+1)^{2}}{36}=1$ $\frac{(y+1)^{2}}{16}-\frac{(x+1)^{2}}{4}=1$ $9 x^{2}-4 y^{2}-18 x+8 y-31=0$ $y^{2}-x^{2}-4 y+2 x-6=0$ $4 y^{2}-16 x^{2}-24 y+96 x-172=0$ \(\fra... $\frac{(y+4)^{2}}{25}-\frac{(x+1)^{2}}{36}=1$ $\frac{(y+1)^{2}}{16}-\frac{(x+1)^{2}}{4}=1$ $9 x^{2}-4 y^{2}-18 x+8 y-31=0$ $y^{2}-x^{2}-4 y+2 x-6=0$ $4 y^{2}-16 x^{2}-24 y+96 x-172=0$ $\frac{(y+1)^{2}}{1}-\frac{(x+2)^{2}}{9}=1$ $x^{2}+y^{2}-4 x+10 y-7=0$ $9 x^{2}-4 y^{2}+54 x+8 y+41=0$ $x=-y^{2}-2 y+3$ Sur une échelle de 1 à 10, comment évalueriez-vous votre maîtrise de cette section à la lumière de vos réponses à la liste de contrôle ? Comment pouvez-vous améliorer cela ?
11.5E: Mazoezi
https://query.libretexts.org/Kiswahili/Algebra_ya_kati_(OpenStax)/11%3A_Conics/11.05%3A_Hyperbolas/11.5E%3A_Mazoezi
$\frac{(y+4)^{2}}{25}-\frac{(x+1)^{2}}{36}=1$ $\frac{(y+1)^{2}}{16}-\frac{(x+1)^{2}}{4}=1$ $\frac{(y-4)^{2}}{16}-\frac{(x+1)^{2}}{25}=1$ $\frac{(x+2)^{2}}{4}-\frac{(y-1)^{2}}{9}=1$ \(9 x^{2}-4... $\frac{(y+4)^{2}}{25}-\frac{(x+1)^{2}}{36}=1$ $\frac{(y+1)^{2}}{16}-\frac{(x+1)^{2}}{4}=1$ $\frac{(y-4)^{2}}{16}-\frac{(x+1)^{2}}{25}=1$ $\frac{(x+2)^{2}}{4}-\frac{(y-1)^{2}}{9}=1$ $9 x^{2}-4 y^{2}-18 x+8 y-31=0$ $y^{2}-x^{2}-4 y+2 x-6=0$ $4 y^{2}-16 x^{2}-24 y+96 x-172=0$ $\frac{(y+1)^{2}}{1}-\frac{(x+2)^{2}}{9}=1$ $\frac{(y-3)^{2}}{9}-\frac{(x+2)^{2}}{16}=1$ $x^{2}+y^{2}-4 x+10 y-7=0$ $9 x^{2}-4 y^{2}+54 x+8 y+41=0$ $x=-y^{2}-2 y+3$
11.5E: Exercícios
https://query.libretexts.org/Idioma_Portugues/Algebra_intermediaria_(OpenStax)/11%3A_C%C3%B4nicas/11.05%3A_Hip%C3%A9rboles/11.5E%3A_Exerc%C3%ADcios
$\frac{(y+4)^{2}}{25}-\frac{(x+1)^{2}}{36}=1$ $\frac{(y+1)^{2}}{16}-\frac{(x+1)^{2}}{4}=1$ $\frac{(y-4)^{2}}{16}-\frac{(x+1)^{2}}{25}=1$ $9 x^{2}-4 y^{2}-18 x+8 y-31=0$ \(y^{2}-x^{2}-4 y+2 x-6... $\frac{(y+4)^{2}}{25}-\frac{(x+1)^{2}}{36}=1$ $\frac{(y+1)^{2}}{16}-\frac{(x+1)^{2}}{4}=1$ $\frac{(y-4)^{2}}{16}-\frac{(x+1)^{2}}{25}=1$ $9 x^{2}-4 y^{2}-18 x+8 y-31=0$ $y^{2}-x^{2}-4 y+2 x-6=0$ $4 y^{2}-16 x^{2}-24 y+96 x-172=0$ $\frac{(y+1)^{2}}{1}-\frac{(x+2)^{2}}{9}=1$ $x^{2}+y^{2}-4 x+10 y-7=0$ $9 x^{2}-4 y^{2}+54 x+8 y+41=0$ $x=-y^{2}-2 y+3$ Explique com suas próprias palavras, como distinguir a equação de uma elipse com a equação de uma hipérbole.