11.5E: Mazoezi
- Page ID
- 176866
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Mazoezi hufanya kamili
Katika mazoezi yafuatayo, grafu.
- \(\frac{x^{2}}{9}-\frac{y^{2}}{4}=1\)
- \(\frac{x^{2}}{25}-\frac{y^{2}}{9}=1\)
- \(\frac{x^{2}}{16}-\frac{y^{2}}{25}=1\)
- \(\frac{x^{2}}{9}-\frac{y^{2}}{36}=1\)
- \(\frac{y^{2}}{25}-\frac{x^{2}}{4}=1\)
- \(\frac{y^{2}}{36}-\frac{x^{2}}{16}=1\)
- \(16 y^{2}-9 x^{2}=144\)
- \(25 y^{2}-9 x^{2}=225\)
- \(4 y^{2}-9 x^{2}=36\)
- \(16 y^{2}-25 x^{2}=400\)
- \(4 x^{2}-16 y^{2}=64\)
- \(9 x^{2}-4 y^{2}=36\)
- Jibu
-
1.
Kielelezo 11.4.33 3.
Kielelezo 11.4.34 5.
Kielelezo 11.4.35 7.
Kielelezo 11.4.36 9.
Kielelezo 11.4.37 11.
Kielelezo 11.4.38
Katika mazoezi yafuatayo, grafu.
- \(\frac{(x-1)^{2}}{16}-\frac{(y-3)^{2}}{4}=1\)
- \(\frac{(x-2)^{2}}{4}-\frac{(y-3)^{2}}{16}=1\)
- \(\frac{(y-4)^{2}}{9}-\frac{(x-2)^{2}}{25}=1\)
- \(\frac{(y-1)^{2}}{25}-\frac{(x-4)^{2}}{16}=1\)
- \(\frac{(y+4)^{2}}{25}-\frac{(x+1)^{2}}{36}=1\)
- \(\frac{(y+1)^{2}}{16}-\frac{(x+1)^{2}}{4}=1\)
- \(\frac{(y-4)^{2}}{16}-\frac{(x+1)^{2}}{25}=1\)
- \(\frac{(y+3)^{2}}{16}-\frac{(x-3)^{2}}{36}=1\)
- \(\frac{(x-3)^{2}}{25}-\frac{(y+2)^{2}}{9}=1\)
- \(\frac{(x+2)^{2}}{4}-\frac{(y-1)^{2}}{9}=1\)
- Jibu
-
1.
Kielelezo 11.4.39 3.
Kielelezo 11.4.40 5.
Kielelezo 11.4.41 7.
Kielelezo 11.4.42 9.
Kielelezo 11.4.43
Katika mazoezi yafuatayo,
- Andika equation katika fomu ya kawaida na
- Grafu.
- \(9 x^{2}-4 y^{2}-18 x+8 y-31=0\)
- \(16 x^{2}-4 y^{2}+64 x-24 y-36=0\)
- \(y^{2}-x^{2}-4 y+2 x-6=0\)
- \(4 y^{2}-16 x^{2}-24 y+96 x-172=0\)
- \(9 y^{2}-x^{2}+18 y-4 x-4=0\)
- Jibu
-
1.
- \(\frac{(x-1)^{2}}{4}-\frac{(y-1)^{2}}{9}=1\)
Kielelezo 11.4.44 3.
- \(\frac{(y-2)^{2}}{9}-\frac{(x-1)^{2}}{9}=1\)
Kielelezo 11.4.45 5.
- \(\frac{(y+1)^{2}}{1}-\frac{(x+2)^{2}}{9}=1\)
Kielelezo 11.4.46
Katika mazoezi yafuatayo, tambua aina ya grafu.
-
- \(x=-y^{2}-2 y+3\)
- \(9 y^{2}-x^{2}+18 y-4 x-4=0\)
- \(9 x^{2}+25 y^{2}=225\)
- \(x^{2}+y^{2}-4 x+10 y-7=0\)
-
- \(x=-2 y^{2}-12 y-16\)
- \(x^{2}+y^{2}=9\)
- \(16 x^{2}-4 y^{2}+64 x-24 y-36=0\)
- \(16 x^{2}+36 y^{2}=576\)
- Jibu
-
2.
- Parabola
- Circle
- Hyperbola
- duaradufu
Katika mazoezi yafuatayo, graph kila equation.
- \(\frac{(y-3)^{2}}{9}-\frac{(x+2)^{2}}{16}=1\)
- \(x^{2}+y^{2}-4 x+10 y-7=0\)
- \(y=(x-1)^{2}+2\)
- \(\frac{x^{2}}{9}+\frac{y^{2}}{25}=1\)
- \((x+2)^{2}+(y-5)^{2}=4\)
- \(9 x^{2}-4 y^{2}+54 x+8 y+41=0\)
- \(x=-y^{2}-2 y+3\)
- \(16 x^{2}+9 y^{2}=144\)
- Jibu
-
2.
Kielelezo 11.4.47 4.
Kielelezo 11.4.48 6.
Kielelezo 11.4.49 8.
Kielelezo 11.4.50
- Kwa maneno yako mwenyewe, fafanua hyperbola na uandike usawa wa hyperbola unaozingatia asili katika fomu ya kawaida. Chora mchoro wa hyperbola kuipatia kituo, vertices, na asymptotes.
- Eleza kwa maneno yako mwenyewe jinsi ya kuunda na kutumia mstatili unaosaidia grafu hyperbola.
- Linganisha na kulinganisha grafu ya equations\(\frac{x^{2}}{4}-\frac{y^{2}}{9}=1\) na\(\frac{y^{2}}{9}-\frac{x^{2}}{4}=1\).
- Eleza kwa maneno yako mwenyewe, jinsi ya kutofautisha equation ya ellipse na equation ya hyperbola.
- Jibu
-
2. Majibu inaweza kutofautiana
4. Majibu inaweza kutofautiana
Self Check
Baada ya kukamilisha mazoezi, tumia orodha hii ili kutathmini ujuzi wako wa malengo ya sehemu hii.
b Kwa kiwango cha 1-10, ungewezaje kupima ujuzi wako wa sehemu hii kwa kuzingatia majibu yako kwenye orodha? Unawezaje kuboresha hii?


