8.4E: تمارين
- Page ID
- 201628
\( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \)
\( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash {#1}}} \)
\( \newcommand{\dsum}{\displaystyle\sum\limits} \)
\( \newcommand{\dint}{\displaystyle\int\limits} \)
\( \newcommand{\dlim}{\displaystyle\lim\limits} \)
\( \newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\)
( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\)
\( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\)
\( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\)
\( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\)
\( \newcommand{\Span}{\mathrm{span}}\)
\( \newcommand{\id}{\mathrm{id}}\)
\( \newcommand{\Span}{\mathrm{span}}\)
\( \newcommand{\kernel}{\mathrm{null}\,}\)
\( \newcommand{\range}{\mathrm{range}\,}\)
\( \newcommand{\RealPart}{\mathrm{Re}}\)
\( \newcommand{\ImaginaryPart}{\mathrm{Im}}\)
\( \newcommand{\Argument}{\mathrm{Arg}}\)
\( \newcommand{\norm}[1]{\| #1 \|}\)
\( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\)
\( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\AA}{\unicode[.8,0]{x212B}}\)
\( \newcommand{\vectorA}[1]{\vec{#1}} % arrow\)
\( \newcommand{\vectorAt}[1]{\vec{\text{#1}}} % arrow\)
\( \newcommand{\vectorB}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \)
\( \newcommand{\vectorC}[1]{\textbf{#1}} \)
\( \newcommand{\vectorD}[1]{\overrightarrow{#1}} \)
\( \newcommand{\vectorDt}[1]{\overrightarrow{\text{#1}}} \)
\( \newcommand{\vectE}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash{\mathbf {#1}}}} \)
\( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \)
\(\newcommand{\longvect}{\overrightarrow}\)
\( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash {#1}}} \)
\(\newcommand{\avec}{\mathbf a}\) \(\newcommand{\bvec}{\mathbf b}\) \(\newcommand{\cvec}{\mathbf c}\) \(\newcommand{\dvec}{\mathbf d}\) \(\newcommand{\dtil}{\widetilde{\mathbf d}}\) \(\newcommand{\evec}{\mathbf e}\) \(\newcommand{\fvec}{\mathbf f}\) \(\newcommand{\nvec}{\mathbf n}\) \(\newcommand{\pvec}{\mathbf p}\) \(\newcommand{\qvec}{\mathbf q}\) \(\newcommand{\svec}{\mathbf s}\) \(\newcommand{\tvec}{\mathbf t}\) \(\newcommand{\uvec}{\mathbf u}\) \(\newcommand{\vvec}{\mathbf v}\) \(\newcommand{\wvec}{\mathbf w}\) \(\newcommand{\xvec}{\mathbf x}\) \(\newcommand{\yvec}{\mathbf y}\) \(\newcommand{\zvec}{\mathbf z}\) \(\newcommand{\rvec}{\mathbf r}\) \(\newcommand{\mvec}{\mathbf m}\) \(\newcommand{\zerovec}{\mathbf 0}\) \(\newcommand{\onevec}{\mathbf 1}\) \(\newcommand{\real}{\mathbb R}\) \(\newcommand{\twovec}[2]{\left[\begin{array}{r}#1 \\ #2 \end{array}\right]}\) \(\newcommand{\ctwovec}[2]{\left[\begin{array}{c}#1 \\ #2 \end{array}\right]}\) \(\newcommand{\threevec}[3]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \end{array}\right]}\) \(\newcommand{\cthreevec}[3]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \end{array}\right]}\) \(\newcommand{\fourvec}[4]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \\ #4 \end{array}\right]}\) \(\newcommand{\cfourvec}[4]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \\ #4 \end{array}\right]}\) \(\newcommand{\fivevec}[5]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \\ #4 \\ #5 \\ \end{array}\right]}\) \(\newcommand{\cfivevec}[5]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \\ #4 \\ #5 \\ \end{array}\right]}\) \(\newcommand{\mattwo}[4]{\left[\begin{array}{rr}#1 \amp #2 \\ #3 \amp #4 \\ \end{array}\right]}\) \(\newcommand{\laspan}[1]{\text{Span}\{#1\}}\) \(\newcommand{\bcal}{\cal B}\) \(\newcommand{\ccal}{\cal C}\) \(\newcommand{\scal}{\cal S}\) \(\newcommand{\wcal}{\cal W}\) \(\newcommand{\ecal}{\cal E}\) \(\newcommand{\coords}[2]{\left\{#1\right\}_{#2}}\) \(\newcommand{\gray}[1]{\color{gray}{#1}}\) \(\newcommand{\lgray}[1]{\color{lightgray}{#1}}\) \(\newcommand{\rank}{\operatorname{rank}}\) \(\newcommand{\row}{\text{Row}}\) \(\newcommand{\col}{\text{Col}}\) \(\renewcommand{\row}{\text{Row}}\) \(\newcommand{\nul}{\text{Nul}}\) \(\newcommand{\var}{\text{Var}}\) \(\newcommand{\corr}{\text{corr}}\) \(\newcommand{\len}[1]{\left|#1\right|}\) \(\newcommand{\bbar}{\overline{\bvec}}\) \(\newcommand{\bhat}{\widehat{\bvec}}\) \(\newcommand{\bperp}{\bvec^\perp}\) \(\newcommand{\xhat}{\widehat{\xvec}}\) \(\newcommand{\vhat}{\widehat{\vvec}}\) \(\newcommand{\uhat}{\widehat{\uvec}}\) \(\newcommand{\what}{\widehat{\wvec}}\) \(\newcommand{\Sighat}{\widehat{\Sigma}}\) \(\newcommand{\lt}{<}\) \(\newcommand{\gt}{>}\) \(\newcommand{\amp}{&}\) \(\definecolor{fillinmathshade}{gray}{0.9}\)الممارسة تجعل من الكمال
في التمارين التالية، اكتب كتعبير جذري.
- أ.\(x^{\frac{1}{2}}\) ب.\(y^{\frac{1}{3}}\) ج.\(z^{\frac{1}{4}}\)
- أ.\(r^{\frac{1}{2}}\) ب.\(s^{\frac{1}{3}}\) ج.\(t^{\frac{1}{4}}\)
- أ.\(u^{\frac{1}{5}}\) ب.\(v^{\frac{1}{9}}\) ج.\(w^{\frac{1}{20}}\)
- أ.\(g^{\frac{1}{7}}\) ب.\(h^{\frac{1}{5}}\) ج.\(j^{\frac{1}{25}}\)
- إجابة
-
1. أ.\(\sqrt{x}\) ب.\(\sqrt[3]{y}\) ج.\(\sqrt[4]{z}\)
3. أ.\(\sqrt[5]{u}\) ب.\(\sqrt[9]{v}\) ج.\(\sqrt[20]{w}\)
في التمارين التالية، اكتب باستخدام الأس النسبي.
- أ.\(\sqrt[7]{x}\) ب.\(\sqrt[9]{y}\) ج.\(\sqrt[5]{f}\)
- أ.\(\sqrt[8]{4}\) ب.\(\sqrt[10]{s}\) ج.\(\sqrt[4]{t}\)
- أ.\(\sqrt[3]{7c}\) ب.\(\sqrt[7]{12d}\) ج.\(2\sqrt[4]{6b}\)
- أ.\(\sqrt[4]{5x}\) ب.\(\sqrt[8]{9y}\) ج.\(7\sqrt[5]{3z}\)
- أ.\(\sqrt{21p}\) ب.\(\sqrt[4]{8q}\) ج.\(4\sqrt[6]{36r}\)
- أ.\(\sqrt[3]{25a}\) ب.\(\sqrt{3b}\) ج.\(\sqrt[8]{40c}\)
- إجابة
-
1. أ.\(x^{\frac{1}{7}}\) ب.\(y^{\frac{1}{9}}\) ج.\(f^{\frac{1}{5}}\)
3. أ.\((7 c)^{\frac{1}{4}}\) ب.\((12 d)^{\frac{1}{7}}\) ج.\(2(6 b)^{\frac{1}{4}}\)
5. أ.\((21 p)^{\frac{1}{2}}\) ب.\((8 q)^{\frac{1}{4}}\) ج.\(4(36 r)^{\frac{1}{6}}\)
في التمارين التالية، قم بالتبسيط.
- أ.\(81^{\frac{1}{2}}\) ب.\(125^{\frac{1}{3}}\) ج.\(64^{\frac{1}{2}}\)
- أ.\(625^{\frac{1}{4}}\) ب.\(243^{\frac{1}{5}}\) ج.\(32^{\frac{1}{5}}\)
- أ.\(16^{\frac{1}{4}}\) ب.\(16^{\frac{1}{2}}\) ج.\(625^{\frac{1}{4}}\)
- أ.\(64^{\frac{1}{3}}\) ب.\(32^{\frac{1}{5}}\) ج.\(81^{\frac{1}{4}}\)
- أ.\((-216)^{\frac{1}{3}}\) ب.\(-216^{\frac{1}{3}}\) ج.\((216)^{-\frac{1}{3}}\)
- أ.\((-1000)^{\frac{1}{3}}\) ب.\(-1000^{\frac{1}{3}}\) ج.\((1000)^{-\frac{1}{3}}\)
- أ.\((-81)^{\frac{1}{4}}\) ب.\(-81^{\frac{1}{4}}\) ج.\((81)^{-\frac{1}{4}}\)
- أ.\((-49)^{\frac{1}{2}}\) ب.\(-49^{\frac{1}{2}}\) ج.\((49)^{-\frac{1}{2}}\)
- أ.\((-36)^{\frac{1}{2}}\) ب.\(-36^{\frac{1}{2}}\) ج.\((36)^{-\frac{1}{2}}\)
- أ.\((-16)^{\frac{1}{4}}\) ب.\(-16^{\frac{1}{4}}\) ج.\(16^{-\frac{1}{4}}\)
- أ.\((-100)^{\frac{1}{2}}\) ب.\(-100^{\frac{1}{2}}\) ج.\((100)^{-\frac{1}{2}}\)
- أ.\((-32)^{\frac{1}{5}}\) ب.\((243)^{-\frac{1}{5}}\) ج.\(-125^{\frac{1}{3}}\)
- إجابة
-
1. أ.\(9\) ب.\(5\) ج.\(8\)
3. أ.\(2\) ب.\(4\) ج.\(5\)
5. أ.\(-6\) ب.\(-6\) ج.\(\frac{1}{6}\)
7. أ. غير حقيقي ب.\(-3\) ج.\(\frac{1}{3}\)
9. أ. غير حقيقي ب.\(-6\) ج.\(\frac{1}{6}\)
11. أ. غير حقيقي ب.\(-10\) ج.\(\frac{1}{10}\)
في التمارين التالية، اكتب باستخدام الأس النسبي.
- أ.\(\sqrt{m^{5}}\) ب.\((\sqrt[3]{3 y})^{7}\) ج.\(\sqrt[5]{\left(\dfrac{4 x}{5 y}\right)^{3}}\)
- أ.\(\sqrt[4]{r^{7}}\) ب.\((\sqrt[5]{2 p q})^{3}\) ج.\(\sqrt[4]{\left(\dfrac{12 m}{7 n}\right)^{3}}\)
- أ.\(\sqrt[5]{u^{2}}\) ب.\((\sqrt[3]{6 x})^{5}\) ج.\(\sqrt[4]{\left(\dfrac{18 a}{5 b}\right)^{7}}\)
- أ.\(\sqrt[3]{a}\) ب.\((\sqrt[4]{21 v})^{3}\) ج.\(\sqrt[4]{\left(\dfrac{2 x y}{5 z}\right)^{2}}\)
- إجابة
-
1. أ.\(m^{\frac{5}{2}}\) ب.\((3 y)^{\frac{7}{3}}\) ج.\(\left(\dfrac{4 x}{5 y}\right)^{\frac{3}{5}}\)
3. أ.\(u^{\frac{2}{5}}\) ب.\((6 x)^{\frac{5}{3}}\) ج.\(\left(\dfrac{18 a}{5 b}\right)^{\frac{7}{4}}\)
في التمارين التالية، قم بالتبسيط.
- أ.\(64^{\frac{5}{2}}\) ب.\(81^{\frac{-3}{2}}\) ج.\((-27)^{\frac{2}{3}}\)
- أ.\(25^{\frac{3}{2}}\) ب.\(9^{-\frac{3}{2}}\) ج.\((-64)^{\frac{2}{3}}\)
- أ.\(32^{\frac{2}{5}}\) ب.\(27^{-\frac{2}{3}}\) ج.\((-25)^{\frac{1}{2}}\)
- أ.\(100^{\frac{3}{2}}\) ب.\(49^{-\frac{5}{2}}\) ج.\((-100)^{\frac{3}{2}}\)
- أ.\(-9^{\frac{3}{2}}\) ب.\(-9^{-\frac{3}{2}}\) ج.\((-9)^{\frac{3}{2}}\)
- أ.\(-64^{\frac{3}{2}}\) ب.\(-64^{-\frac{3}{2}}\) ج.\((-64)^{\frac{3}{2}}\)
- إجابة
-
1. أ.\(32,768\) ب.\(\frac{1}{729}\) ج.\(9\)
3. أ.\(4\) ب.\(\frac{1}{9}\) ج. غير حقيقي
5. أ.\(-27\) ب.\(-\frac{1}{27}\) ج. غير حقيقي
في التمارين التالية، قم بالتبسيط. افترض أن جميع المتغيرات إيجابية.
- أ.\(c^{\frac{1}{4}} \cdot c^{\frac{5}{8}}\) ب.\(\left(p^{12}\right)^{\frac{3}{4}}\) ج.\(\dfrac{r^{\frac{4}{5}}}{r^{\frac{9}{5}}}\)
- أ.\(6^{\frac{5}{2}} \cdot 6^{\frac{1}{2}}\) ب.\(\left(b^{15}\right)^{\frac{3}{5}}\) ج.\(\dfrac{w^{\frac{2}{7}}}{w^{\frac{9}{7}}}\)
- أ.\(y^{\frac{1}{2}} \cdot y^{\frac{3}{4}}\) ب.\(\left(x^{12}\right)^{\frac{2}{3}}\) ج.\(\dfrac{m^{\frac{5}{8}}}{m^{\frac{13}{8}}}\)
- أ.\(q^{\frac{2}{3}} \cdot q^{\frac{5}{6}}\) ب.\(\left(h^{6}\right)^{\frac{4}{3}}\) ج.\(\dfrac{n^{\frac{3}{5}}}{n^{\frac{8}{5}}}\)
- أ.\(\left(27 q^{\frac{3}{2}}\right)^{\frac{4}{3}}\) ب.\(\left(a^{\frac{1}{3}} b^{\frac{2}{3}}\right)^{\frac{3}{2}}\)
- أ.\(\left(64 s^{\frac{3}{7}}\right)^{\frac{1}{6}}\) ب.\(\left(m^{\frac{4}{3}} n^{\frac{1}{2}}\right)^{\frac{3}{4}}\)
- أ.\(\left(16 u^{\frac{1}{3}}\right)^{\frac{3}{4}}\) ب.\(\left(4 p^{\frac{1}{3}} q^{\frac{1}{2}}\right)^{\frac{3}{2}}\)
- أ.\(\left(625 n^{\frac{8}{3}}\right)^{\frac{3}{4}}\) ب.\(\left(9 x^{\frac{2}{5}} y^{\frac{3}{5}}\right)^{\frac{5}{2}}\)
- أ.\(\dfrac{r^{\frac{5}{2}} \cdot r^{-\frac{1}{2}}}{r^{-\frac{3}{2}}}\) ب.\(\left(\dfrac{36 s^{\frac{1}{5}} t^{-\frac{3}{2}}}{s^{-\frac{9}{5}} t^{\frac{1}{2}}}\right)^{\frac{1}{2}}\)
- أ.\(\dfrac{a^{\frac{3}{4}} \cdot a^{-\frac{1}{4}}}{a^{-\frac{10}{4}}}\) ب.\(\left(\dfrac{27 b^{\frac{2}{3}} c^{-\frac{5}{2}}}{b^{-\frac{7}{3}} c^{\frac{1}{2}}}\right)^{\frac{1}{3}}\)
- أ.\(\dfrac{c^{\frac{5}{3}} \cdot c^{-\frac{1}{3}}}{c^{-\frac{2}{3}}}\) ب.\(\left(\dfrac{8 x^{\frac{5}{3}} y^{-\frac{1}{2}}}{27 x^{-\frac{4}{3}} y^{\frac{5}{2}}}\right)^{\frac{1}{3}}\)
- أ.\(\dfrac{m^{\frac{7}{4}} \cdot m^{-\frac{5}{4}}}{m^{-\frac{2}{4}}}\) ب.\(\left(\dfrac{16 m^{\frac{1}{5}} n^{\frac{3}{2}}}{81 m^{\frac{9}{5}} n^{-\frac{1}{2}}}\right)^{\frac{1}{4}}\)
- إجابة
-
1. أ.\(c^{\frac{7}{8}}\) ب.\(p^{9}\) ج.\(\frac{1}{r}\)
3. أ.\(y^{\frac{5}{4}}\) ب.\(x^{8}\) ج.\(\dfrac{1}{m}\)
5. أ.\(81 q^{2}\) ب.\(a^{\frac{1}{2}} b\)
7. أ.\(8 u^{\frac{1}{4}}\) ب.\(8 p^{\frac{1}{2}} q^{\frac{3}{4}}\)
9. أ.\(r^{\frac{7}{2}}\) ب.\(\dfrac{6 s}{t}\)
11. أ.\(c^{2}\) ب.\(\dfrac{2x}{3y}\)
- اعرض طريقتين جبريتين مختلفتين للتبسيط\(4^{\frac{3}{2}}\). اشرح جميع خطواتك.
- اشرح لماذا\((-16)^{\frac{3}{2}}\) لا يمكن تقييم التعبير.
- إجابة
-
1. سوف تتنوع الإجابات.
فحص ذاتي
أ- بعد الانتهاء من التمارين، استخدم قائمة التحقق هذه لتقييم مدى إتقانك لأهداف هذا القسم.
ب- ماذا تخبرك قائمة التحقق هذه عن إتقانك لهذا القسم؟ ما الخطوات التي ستتخذها للتحسين؟


