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2.9 : Examen de la formule des chapitres
https://query.libretexts.org/Francais/Livre_%3A_Statistiques_commerciales_(OpenStax)/02%3A_Statistiques_descriptives/2.09%3A_Examen_de_la_formule_des_chapitres
Formules pour l'écart type de la population\(\sigma=\sqrt{\frac{\Sigma(x-\mu)^{2}}{N}} \text { or } \sigma=\sqrt{\frac{\Sigma f(x \mu)^{2}}{N}} \text { or } \sigma=\sqrt{\frac{\sum_{i=1}^{N} x_{i}^{2}...Formules pour l'écart type de la population $\sigma=\sqrt{\frac{\Sigma(x-\mu)^{2}}{N}} \text { or } \sigma=\sqrt{\frac{\Sigma f(x \mu)^{2}}{N}} \text { or } \sigma=\sqrt{\frac{\sum_{i=1}^{N} x_{i}^{2}}{N}-\mu^{2} F}$ Pour l'écart type de la population, le dénominateur est N, le nombre d'éléments de la population.
2.9: Sura ya Tathmini ya Mfumo
https://query.libretexts.org/Kiswahili/Kitabu%3A_Takwimu_za_Biashara_(OpenStax)/02%3A_Takwimu_za_maelezo/2.09%3A_Sura_ya_Tathmini_ya_Mfumo
Mfumo wa Kupotoka $\sigma=\sqrt{\frac{\Sigma(x-\mu)^{2}}{N}} \text { or } \sigma=\sqrt{\frac{\Sigma f(x \mu)^{2}}{N}} \text { or } \sigma=\sqrt{\frac{\sum_{i=1}^{N} x_{i}^{2}}{N}-\mu^{2} F}$ kwa kiwa...Mfumo wa Kupotoka $\sigma=\sqrt{\frac{\Sigma(x-\mu)^{2}}{N}} \text { or } \sigma=\sqrt{\frac{\Sigma f(x \mu)^{2}}{N}} \text { or } \sigma=\sqrt{\frac{\sum_{i=1}^{N} x_{i}^{2}}{N}-\mu^{2} F}$ kwa kiwango cha Idadi ya Watu Kwa kupotoka kwa kiwango cha idadi ya watu, denominator ni N, idadi ya vitu katika idadi ya watu.
2.9: Revisão da fórmula do capítulo
https://query.libretexts.org/Idioma_Portugues/Livro%3A_Estatisticas_de_negocios_(OpenStax)/02%3A_Estat%C3%ADsticas_descritivas/2.09%3A_Revis%C3%A3o_da_f%C3%B3rmula_do_cap%C3%ADtulo
Fórmulas para desvio padrão da população\(\sigma=\sqrt{\frac{\Sigma(x-\mu)^{2}}{N}} \text { or } \sigma=\sqrt{\frac{\Sigma f(x \mu)^{2}}{N}} \text { or } \sigma=\sqrt{\frac{\sum_{i=1}^{N} x_{i}^{2}}{N...Fórmulas para desvio padrão da população $\sigma=\sqrt{\frac{\Sigma(x-\mu)^{2}}{N}} \text { or } \sigma=\sqrt{\frac{\Sigma f(x \mu)^{2}}{N}} \text { or } \sigma=\sqrt{\frac{\sum_{i=1}^{N} x_{i}^{2}}{N}-\mu^{2} F}$ Para o desvio padrão da população, o denominador é N, o número de itens na população.
2.9: 章节公式回顾
https://query.libretexts.org/%E7%AE%80%E4%BD%93%E4%B8%AD%E6%96%87/%E5%9B%BE%E4%B9%A6%EF%BC%9A%E5%95%86%E4%B8%9A%E7%BB%9F%E8%AE%A1_(OpenStax)/02%3A_%E6%8F%8F%E8%BF%B0%E6%80%A7%E7%BB%9F%E8%AE%A1/2.09%3A_%E7%AB%A0%E8%8A%82%E5%85%AC%E5%BC%8F%E5%9B%9E%E9%A1%BE
样本标准差公式 $s=\sqrt{\frac{\Sigma(x-\overline{x})^{2}}{n-1}} \text { or } s=\sqrt{\frac{\Sigma f(x-\overline{x})^{2}}{n-1}} \text { or } s=\sqrt{\frac{\left(\sum_{t=1}^{n} x^{2}\right)-n x^{2}}{n-1}}$ 对于样...样本标准差公式 $s=\sqrt{\frac{\Sigma(x-\overline{x})^{2}}{n-1}} \text { or } s=\sqrt{\frac{\Sigma f(x-\overline{x})^{2}}{n-1}} \text { or } s=\sqrt{\frac{\left(\sum_{t=1}^{n} x^{2}\right)-n x^{2}}{n-1}}$ 对于样本标准差，分母为 n-1，即样本数量-1。总体标准差 $\sigma=\sqrt{\frac{\Sigma(x-\mu)^{2}}{N}} \text { or } \sigma=\sqrt{\frac{\Sigma f(x \mu)^{2}}{N}} \text { or } \sigma=\sqrt{\frac{\sum_{i=1}^{N} x_{i}^{2}}{N}-\mu^{2} F}$ 的公式对于总体标准差，分母为 N，即总体中的项目数。
2.9: مراجعة صيغة الفصل
https://query.libretexts.org/%D8%A7%D9%84%D9%84%D8%BA%D8%A9_%D8%A7%D9%84%D8%B9%D8%B1%D8%A8%D9%8A%D8%A9/%D9%83%D8%AA%D8%A7%D8%A8%3A_%D8%A5%D8%AD%D8%B5%D8%A7%D8%A1%D8%A7%D8%AA_%D8%A7%D9%84%D8%A3%D8%B9%D9%85%D8%A7%D9%84_(OpenStax)/02%3A/2.09%3A_%D9%85%D8%B1%D8%A7%D8%AC%D8%B9%D8%A9_%D8%B5%D9%8A%D8%BA%D8%A9_%D8%A7%D9%84%D9%81%D8%B5%D9%84
معادلات الانحراف المعياري للسكان\(\sigma=\sqrt{\frac{\Sigma(x-\mu)^{2}}{N}} \text { or } \sigma=\sqrt{\frac{\Sigma f(x \mu)^{2}}{N}} \text { or } \sigma=\sqrt{\frac{\sum_{i=1}^{N} x_{i}^{2}}{N}-\mu^{2...معادلات الانحراف المعياري للسكان $\sigma=\sqrt{\frac{\Sigma(x-\mu)^{2}}{N}} \text { or } \sigma=\sqrt{\frac{\Sigma f(x \mu)^{2}}{N}} \text { or } \sigma=\sqrt{\frac{\sum_{i=1}^{N} x_{i}^{2}}{N}-\mu^{2} F}$ بالنسبة للانحراف المعياري للسكان، فإن المقام هو N، وهو عدد العناصر في المجموعة السكانية.