5.9: 有理指数
- Page ID
- 171036
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\(\newcommand{\avec}{\mathbf a}\) \(\newcommand{\bvec}{\mathbf b}\) \(\newcommand{\cvec}{\mathbf c}\) \(\newcommand{\dvec}{\mathbf d}\) \(\newcommand{\dtil}{\widetilde{\mathbf d}}\) \(\newcommand{\evec}{\mathbf e}\) \(\newcommand{\fvec}{\mathbf f}\) \(\newcommand{\nvec}{\mathbf n}\) \(\newcommand{\pvec}{\mathbf p}\) \(\newcommand{\qvec}{\mathbf q}\) \(\newcommand{\svec}{\mathbf s}\) \(\newcommand{\tvec}{\mathbf t}\) \(\newcommand{\uvec}{\mathbf u}\) \(\newcommand{\vvec}{\mathbf v}\) \(\newcommand{\wvec}{\mathbf w}\) \(\newcommand{\xvec}{\mathbf x}\) \(\newcommand{\yvec}{\mathbf y}\) \(\newcommand{\zvec}{\mathbf z}\) \(\newcommand{\rvec}{\mathbf r}\) \(\newcommand{\mvec}{\mathbf m}\) \(\newcommand{\zerovec}{\mathbf 0}\) \(\newcommand{\onevec}{\mathbf 1}\) \(\newcommand{\real}{\mathbb R}\) \(\newcommand{\twovec}[2]{\left[\begin{array}{r}#1 \\ #2 \end{array}\right]}\) \(\newcommand{\ctwovec}[2]{\left[\begin{array}{c}#1 \\ #2 \end{array}\right]}\) \(\newcommand{\threevec}[3]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \end{array}\right]}\) \(\newcommand{\cthreevec}[3]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \end{array}\right]}\) \(\newcommand{\fourvec}[4]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \\ #4 \end{array}\right]}\) \(\newcommand{\cfourvec}[4]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \\ #4 \end{array}\right]}\) \(\newcommand{\fivevec}[5]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \\ #4 \\ #5 \\ \end{array}\right]}\) \(\newcommand{\cfivevec}[5]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \\ #4 \\ #5 \\ \end{array}\right]}\) \(\newcommand{\mattwo}[4]{\left[\begin{array}{rr}#1 \amp #2 \\ #3 \amp #4 \\ \end{array}\right]}\) \(\newcommand{\laspan}[1]{\text{Span}\{#1\}}\) \(\newcommand{\bcal}{\cal B}\) \(\newcommand{\ccal}{\cal C}\) \(\newcommand{\scal}{\cal S}\) \(\newcommand{\wcal}{\cal W}\) \(\newcommand{\ecal}{\cal E}\) \(\newcommand{\coords}[2]{\left\{#1\right\}_{#2}}\) \(\newcommand{\gray}[1]{\color{gray}{#1}}\) \(\newcommand{\lgray}[1]{\color{lightgray}{#1}}\) \(\newcommand{\rank}{\operatorname{rank}}\) \(\newcommand{\row}{\text{Row}}\) \(\newcommand{\col}{\text{Col}}\) \(\renewcommand{\row}{\text{Row}}\) \(\newcommand{\nul}{\text{Nul}}\) \(\newcommand{\var}{\text{Var}}\) \(\newcommand{\corr}{\text{corr}}\) \(\newcommand{\len}[1]{\left|#1\right|}\) \(\newcommand{\bbar}{\overline{\bvec}}\) \(\newcommand{\bhat}{\widehat{\bvec}}\) \(\newcommand{\bperp}{\bvec^\perp}\) \(\newcommand{\xhat}{\widehat{\xvec}}\) \(\newcommand{\vhat}{\widehat{\vvec}}\) \(\newcommand{\uhat}{\widehat{\uvec}}\) \(\newcommand{\what}{\widehat{\wvec}}\) \(\newcommand{\Sighat}{\widehat{\Sigma}}\) \(\newcommand{\lt}{<}\) \(\newcommand{\gt}{>}\) \(\newcommand{\amp}{&}\) \(\definecolor{fillinmathshade}{gray}{0.9}\)指数并不总是整数。 本节将探讨指数是有理数的情况。 当指数是有理数时,表达式可以写成带有激进的表达式。 规则是用与原始问题相同的形式写出答案(如果你以指数开头,以指数结尾,或者如果你以激进开头,以激进结尾)。
对于任何实数\(a\)和任何整数\(n\),指数为的表达式\(\dfrac{1}{n}\)可以表示为如下所示
\[a^{\frac{1}{n}} = \sqrt[n]{a} \nonumber \]
注意:\(n\)是激进中的索引。 \(\sqrt[n]{a}\)被读为 “a 的第 n 个根”
注意:当激进没有可见索引时,默认情况下,索引为\(2\)(平方根)。 大于的指数\(2\)将在激进部分上标出。
- \((4)^{\frac{1}{2}} = \sqrt{4} = 2\)\(\text{Index is \(2\)默认}\)
- \( (x)^{\frac{1}{7}} = \sqrt[7]{x}\)\(\text{Index is \(7\)}\)
- \((−3y)^{\frac{1}{3}} = \sqrt[3]{(-3y)}\)\(\text{Index is \(3\)}\)
现在,让我们观察一下当指数是带有分子的有理数时会发生什么\(\neq 1\)。
对于任何实数\(a\)和任何整数\(n\)和\(m\),指数为的表达式\(\dfrac{m}{n}\)可以表示为如下所示
\[a^{\frac{m}{n}} = \sqrt[n]{a^m} \text{ or } (\sqrt[n]{a})^m \nonumber \]
注意:\(n\)是激进中的索引,\(m\)是基数的力量。
用激进的形式写下以下内容
- \((x)^{\frac{2}{3}} = \sqrt[3]{x^2} = (\sqrt[3]{x})^2\)\(\text{Index is \(3\)并将 base 提升到\(2\)。}\)
- \((5t)^{\frac{7}{8}} = \sqrt[8]{5t^7} = (\sqrt[8]{5t})^7\)\(\text{Index is \(8\)然后 base 被提升到\(7\)力量。}\)
- \((x)^{\frac{2}{3}} = \sqrt[3]{x^2} = (\sqrt[3]{x})^2\)\(\text{Index is \(3\)然后将基地提升到权力\(2\)。}\)
- \(\begin{array} &&(z)^{−\frac{5}{9}} &\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\text{Given} \\ &= \dfrac{1}{(z)^{\frac{5}{9}}} &\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\text{Negative exponent rule applied} \\ &= \dfrac{1}{\sqrt[9]{x^5}} \text{ or } \left( \dfrac{1}{\sqrt[9]{x}} \right)^5 &\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\text{Rational exponent written as a radical.} \end{array}\)
- \(\left( \dfrac{3}{4} \right)^{\frac{5}{7}} = \sqrt[7]{\dfrac{3}{4}^5}\)\(\text{Rational exponent written as radical with index \(7\)然后 base 提升到\(5\)了。}\)
用激进的形式写下以下内容。
- \((x)^{\frac{5}{7}}\)
- \((xy)^{\frac{9}{8}}\)
- \((x)^{\frac{9}{5}}\)
- \((z)^{−\frac{11}{13}}\)
- \(\left( \dfrac{x}{4} \right)^{\frac{6}{9}}\)
- \(6(y)^{\frac{1}{17}}\)
- \((6y)^{\frac{1}{17}}\)
- \(\left( \dfrac{3}{4} \right)^{\frac{x}{y}}\)
- \(\left( \dfrac{7}{4} \right)^{(−\frac{x}{y})}\)


