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10.5 : Deux moyennes de population avec des écarts types connus
https://query.libretexts.org/Francais/Livre_%3A_Statistiques_commerciales_(OpenStax)/10%3A_Test_d'hypoth%C3%A8se_avec_deux_%C3%A9chantillons/10.05%3A_Deux_moyennes_de_population_avec_des_%C3%A9carts_types_connus
La distribution normale a le format suivant : $\textbf{The standard deviation is:}\nonumber$ $\sqrt{\frac{\left(\sigma_{1}\right)^{2}}{n_{1}}+\frac{\left(\sigma_{2}\right)^{2}}{n_{2}}}\nonumber$ \...La distribution normale a le format suivant : $\textbf{The standard deviation is:}\nonumber$ $\sqrt{\frac{\left(\sigma_{1}\right)^{2}}{n_{1}}+\frac{\left(\sigma_{2}\right)^{2}}{n_{2}}}\nonumber$ $\textbf{The test statistic (z-score) is:}\nonumber$ $Z_{c}=\frac{\left(\overline{x}_{1}-\overline{x}_{2}\right)-\delta_{0}}{\sqrt{\frac{\left(\sigma_{1}\right)^{2}}{n_{1}}+\frac{\left(\sigma_{2}\right)^{2}}{n_{2}}}}\nonumber$ Au seuil de signification de 5 %, les données de l'échantillon ne per…
10.5：具有已知标准差的两个总体均值
https://query.libretexts.org/%E7%AE%80%E4%BD%93%E4%B8%AD%E6%96%87/%E5%9B%BE%E4%B9%A6%EF%BC%9A%E5%95%86%E4%B8%9A%E7%BB%9F%E8%AE%A1_(OpenStax)/10%3A_10%EF%BC%9A%E4%BD%BF%E7%94%A8%E4%B8%A4%E4%B8%AA%E6%A0%B7%E6%9C%AC%E8%BF%9B%E8%A1%8C%E5%81%87%E8%AE%BE%E6%A3%80%E9%AA%8C/10.05%3A_10.5%EF%BC%9A%E5%85%B7%E6%9C%89%E5%B7%B2%E7%9F%A5%E6%A0%87%E5%87%86%E5%B7%AE%E7%9A%84%E4%B8%A4%E4%B8%AA%E6%80%BB%E4%BD%93%E5%9D%87%E5%80%BC
尽管这种情况不太可能（知道总体标准差的可能性很小），但以下示例说明了对具有已知总体标准差的独立均值的假设检验。根据中心极限定理，均值之间差值的抽样分布是正态的。随机变量是 $\overline{X_{1}}-\overline{X_{2}}$ 。正态分布采用以下格式： $\textbf{The standard deviation is:}\nonumber$ \[\sqrt{\frac...尽管这种情况不太可能（知道总体标准差的可能性很小），但以下示例说明了对具有已知总体标准差的独立均值的假设检验。根据中心极限定理，均值之间差值的抽样分布是正态的。随机变量是 $\overline{X_{1}}-\overline{X_{2}}$ 。正态分布采用以下格式： $\textbf{The standard deviation is:}\nonumber$ $\sqrt{\frac{\left(\sigma_{1}\right)^{2}}{n_{1}}+\frac{\left(\sigma_{2}\right)^{2}}{n_{2}}}\nonumber$ $\textbf{The test statistic (z-score) is:}\nonumber$ \[Z_{c}=\frac{\left(\overline{x}_{1}-\overline{x}_{2}\right)-\delta_{0}}{\sqrt{\frac{\left(\sigma_{1}\right)^{2}}{n_{1}}+\frac{\left(\sigma_{2}\right)^{2…
10.5: Duas médias populacionais com desvios padrão conhecidos
https://query.libretexts.org/Idioma_Portugues/Livro%3A_Estatisticas_de_negocios_(OpenStax)/10%3A_Teste_de_hip%C3%B3teses_com_duas_amostras/10.05%3A_Duas_m%C3%A9dias_populacionais_com_desvios_padr%C3%A3o_conhecidos
A distribuição normal tem o seguinte formato: $\textbf{The standard deviation is:}\nonumber$ $\sqrt{\frac{\left(\sigma_{1}\right)^{2}}{n_{1}}+\frac{\left(\sigma_{2}\right)^{2}}{n_{2}}}\nonumber$ \...A distribuição normal tem o seguinte formato: $\textbf{The standard deviation is:}\nonumber$ $\sqrt{\frac{\left(\sigma_{1}\right)^{2}}{n_{1}}+\frac{\left(\sigma_{2}\right)^{2}}{n_{2}}}\nonumber$ $\textbf{The test statistic (z-score) is:}\nonumber$ $Z_{c}=\frac{\left(\overline{x}_{1}-\overline{x}_{2}\right)-\delta_{0}}{\sqrt{\frac{\left(\sigma_{1}\right)^{2}}{n_{1}}+\frac{\left(\sigma_{2}\right)^{2}}{n_{2}}}}\nonumber$ No nível de significância de 5%, a partir dos dados da amostra, não h…
10.5: وسيلتان سكانيتان لهما انحرافات معيارية معروفة
https://query.libretexts.org/%D8%A7%D9%84%D9%84%D8%BA%D8%A9_%D8%A7%D9%84%D8%B9%D8%B1%D8%A8%D9%8A%D8%A9/%D9%83%D8%AA%D8%A7%D8%A8%3A_%D8%A5%D8%AD%D8%B5%D8%A7%D8%A1%D8%A7%D8%AA_%D8%A7%D9%84%D8%A3%D8%B9%D9%85%D8%A7%D9%84_(OpenStax)/10%3A/10.05%3A_%D9%88%D8%B3%D9%8A%D9%84%D8%AA%D8%A7%D9%86_%D8%B3%D9%83%D8%A7%D9%86%D9%8A%D8%AA%D8%A7%D9%86_%D9%84%D9%87%D9%85%D8%A7_%D8%A7%D9%86%D8%AD%D8%B1%D8%A7%D9%81%D8%A7%D8%AA_%D9%85%D8%B9%D9%8A%D8%A7%D8%B1%D9%8A%D8%A9_%D9%85%D8%B9%D8%B1%D9%88%D9%81%D8%A9
يحتوي التوزيع العادي على التنسيق التالي: $\textbf{The standard deviation is:}\nonumber$ $\sqrt{\frac{\left(\sigma_{1}\right)^{2}}{n_{1}}+\frac{\left(\sigma_{2}\right)^{2}}{n_{2}}}\nonumber$ \[\tex...يحتوي التوزيع العادي على التنسيق التالي: $\textbf{The standard deviation is:}\nonumber$ $\sqrt{\frac{\left(\sigma_{1}\right)^{2}}{n_{1}}+\frac{\left(\sigma_{2}\right)^{2}}{n_{2}}}\nonumber$ $\textbf{The test statistic (z-score) is:}\nonumber$ $Z_{c}=\frac{\left(\overline{x}_{1}-\overline{x}_{2}\right)-\delta_{0}}{\sqrt{\frac{\left(\sigma_{1}\right)^{2}}{n_{1}}+\frac{\left(\sigma_{2}\right)^{2}}{n_{2}}}}\nonumber$ على مستوى الأهمية البالغ 5٪، من بيانات العينة، لا توجد أدلة كافية لاستنتاج…
10.5: Njia mbili za Idadi ya Watu na Mapungufu ya Kiwango cha Kujulikana
https://query.libretexts.org/Kiswahili/Kitabu%3A_Takwimu_za_Biashara_(OpenStax)/10%3A_Kupima_hypothesis_na_Sampuli_mbili/10.05%3A_Njia_mbili_za_Idadi_ya_Watu_na_Mapungufu_ya_Kiwango_cha_Kujulikana
Usambazaji wa kawaida una muundo wafuatayo: $\textbf{The standard deviation is:}\nonumber$ $\sqrt{\frac{\left(\sigma_{1}\right)^{2}}{n_{1}}+\frac{\left(\sigma_{2}\right)^{2}}{n_{2}}}\nonumber$ \[\...Usambazaji wa kawaida una muundo wafuatayo: $\textbf{The standard deviation is:}\nonumber$ $\sqrt{\frac{\left(\sigma_{1}\right)^{2}}{n_{1}}+\frac{\left(\sigma_{2}\right)^{2}}{n_{2}}}\nonumber$ $\textbf{The test statistic (z-score) is:}\nonumber$ $Z_{c}=\frac{\left(\overline{x}_{1}-\overline{x}_{2}\right)-\delta_{0}}{\sqrt{\frac{\left(\sigma_{1}\right)^{2}}{n_{1}}+\frac{\left(\sigma_{2}\right)^{2}}{n_{2}}}}\nonumber$ Katika kiwango cha 5% cha umuhimu, kutoka kwa data ya sampuli, hakuna u…