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- https://query.libretexts.org/Idioma_Portugues/Fisica_Universitaria_I_-_Mecanica_Som_Oscilacoes_e_Ondas_(OpenStax)/02%3A_Vetores/2.07%3A_Exemplos_de_%C3%A1lgebra_de_vetoresO vetor de deslocamento→DAB é a soma vetorial do vetor de deslocamento do corredor→DAT ao longo da escada (do ponto A na parte inferior da escada ao ponto T no topo da escada) ...O vetor de deslocamento→DAB é a soma vetorial do vetor de deslocamento do corredor→DAT ao longo da escada (do ponto A na parte inferior da escada ao ponto T no topo da escada) e seu vetor de deslocamento→DRB no topo da colina (do ponto T no topo da escada até o fonte no ponto B).
- https://query.libretexts.org/%D8%A7%D9%84%D9%84%D8%BA%D8%A9_%D8%A7%D9%84%D8%B9%D8%B1%D8%A8%D9%8A%D8%A9/-_____(OpenStax)/02%3A_%D8%A7%D9%84%D9%85%D8%AA%D8%AC%D9%87%D8%A7%D8%AA/2.07%3A_%D8%A3%D9%85%D8%AB%D9%84%D8%A9_%D8%AC%D8%A8%D8%B1_%D8%A7%D9%84%D9%85%D8%AA%D8%AC%D9%87%D8%A7%D8%AA\[ \vec{S} = \vec{A} - 3 \vec{B} + \vec{C} = (A_{x} \hat{i} + A_{y} \hat{j}) - 3(B_{x} \hat{i} + B_{y} \hat{j}) + (C_{x} \hat{i} + C_{y} \hat{j}) = (A_{x} - 3 B_{x} + C_{x}) \hat{i} + (A_{y} - 3 B_{y}...→S=→A−3→B+→C=(Axˆi+Ayˆj)−3(Bxˆi+Byˆj)+(Cxˆi+Cyˆj)=(Ax−3Bx+Cx)ˆi+(Ay−3By+Cy)ˆj.
- https://query.libretexts.org/Kiswahili/Chuo_Kikuu_Fizikia_I_-_Mitambo%2C_Sauti%2C_oscillations%2C_na_Waves_(OpenStax)/02%3A_wadudu/2.07%3A_Algebra_ya_Vectors_MifanoVector ya uhamisho→DAB ni jumla ya vector ya vector→DAT ya uhamisho wa jogger kwenye ngazi (kutoka hatua A chini ya ngazi hadi kumweka T juu ya ngazi) na vector→DRB...Vector ya uhamisho→DAB ni jumla ya vector ya vector→DAT ya uhamisho wa jogger kwenye ngazi (kutoka hatua A chini ya ngazi hadi kumweka T juu ya ngazi) na vector→DRB yake ya makazi yao juu ya kilima (kutoka hatua ya T juu ya ngazi chemchemi katika hatua B).
- https://query.libretexts.org/Francais/Physique_universitaire_I_-_M%C3%A9canique%2C_son%2C_oscillations_et_ondes_(OpenStax)/02%3A_Vecteurs/2.07%3A_Exemples_d'alg%C3%A8bre_de_vecteursLe vecteur de déplacement→DAB est la somme vectorielle du vecteur de déplacement du joggeur le→DAT long des escaliers (du point A en bas de l'escalier au point T en haut de l'e...Le vecteur de déplacement→DAB est la somme vectorielle du vecteur de déplacement du joggeur le→DAT long des escaliers (du point A en bas de l'escalier au point T en haut de l'escalier) et de son vecteur→DRB de déplacement en haut de la colline (du point T en haut de l'escalier jusqu'au fontaine au point B).
- https://query.libretexts.org/%E7%AE%80%E4%BD%93%E4%B8%AD%E6%96%87/%E5%A4%A7%E5%AD%A6%E7%89%A9%E7%90%86%E5%AD%A6_I-%E5%8A%9B%E5%AD%A6%E3%80%81%E5%A3%B0%E9%9F%B3%E3%80%81%E6%8C%AF%E8%8D%A1%E5%92%8C%E6%B3%A2%E6%B5%AA_(OpenStax)/02%3A_%E5%90%91%E9%87%8F/2.07%3A_%E5%90%91%E9%87%8F%E4%BB%A3%E6%95%B0%E7%A4%BA%E4%BE%8B\[ \vec{S} = \vec{A} - 3 \vec{B} + \vec{C} = (A_{x} \hat{i} + A_{y} \hat{j}) - 3(B_{x} \hat{i} + B_{y} \hat{j}) + (C_{x} \hat{i} + C_{y} \hat{j}) = (A_{x} - 3 B_{x} + C_{x}) \hat{i} + (A_{y} - 3 B_{y}...→S=→A−3→B+→C=(Axˆi+Ayˆj)−3(Bxˆi+Byˆj)+(Cxˆi+Cyˆj)=(Ax−3Bx+Cx)ˆi+(Ay−3By+Cy)ˆj.