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18.2: Vectors

  • Page ID
    176797
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    Angalia Uelewa Wako

    2.1. a. si sawa kwa sababu wao ni orthogonal; b. si sawa kwa sababu wana ukubwa tofauti; c. si sawa kwa sababu wana ukubwa tofauti na maelekezo; d. si sawa kwa sababu wao ni antiparallel; e. sawa.

    2.2. 16 m;\(\vec{D}\) = -16 m\(\hat{u}\)

    2.3. G = 28.2 cm,\(\theta_{G}\) = 291°

    2.4. \(\vec{D}\)= (-5.0\(\hat{i}\) - 3.0\(\hat{j}\)) cm; kuruka ilihamia 5.0 cm upande wa kushoto na 3.0 cm chini kutoka kwenye tovuti yake ya kutua.

    2.5. 5.83 sentimita, 211°

    2.6. \(\vec{D}\)= (-20 m)\(\hat{j}\)

    2.7. 35.1 m/s = 126.4 km/h

    2.8. \(\vec{G}\)= (10.25 ÷\(\hat{i}\) 26.22\(\hat{j}\)) sentimita

    2.9. D = 55.7 N; mwelekeo 65.7° kaskazini mwa mashariki

    2.10. \(\hat{v}\)= 0.8\(\hat{i}\) + 0.6\(\hat{j}\), 36.87° kaskazini mwa mashariki

    2.11. \(\vec{A} \cdotp \vec{B}\)= -57.3,\(\vec{F} \cdotp \vec{C}\) = 27.8

    2.13. 131.9°

    2.14. W 1 = 1.5 J, W 2 = 0.3 J

    2.15. \(\vec{A} \times \vec{B}\)= -40.1\(\hat{k}\) au, sawa,\(\vec{A} \times \vec{B}\) | = 40.1, na mwelekeo ni ndani ya ukurasa;\(\vec{C} \times \vec{F}\) = + 157.6\(\hat{k}\) au, sawa, |\(\vec{C} \times \vec{F}\) | = 157.6, na mwelekeo hauko nje ya ukurasa.

    2.16. a. -2\(\hat{k}\), b. 2, c. 153.4°, d. 135°

    Maswali ya dhana

    1. Scalar

    3. Majibu inaweza kutofautiana

    5. Sambamba, jumla ya ukubwa, antiparallel, sifuri

    7. Ndiyo, ndiyo

    9. Zero, ndiyo

    11. Hapana

    13. Sawa, sawa, sawa

    15. Vector kitengo cha x-axis

    17. Wao ni sawa.

    19. Ndiyo

    21. a. C =\(\vec{A} \cdotp \vec{B}\), b.\(\vec{C} = \vec{A} \times \vec{B}\) au\(\vec{C} = \vec{A} - \vec{B}\), c.\(\vec{C} = \vec{A} \times\vec{B}\), d.\(\vec{C}\) = A\(\vec{B}\), e., f.\(\vec{C} + 2 \vec{A} = \vec{B}\)\(\vec{C} = \vec{A} \times \vec{B}\), g. upande wa kushoto ni scalar na upande wa kulia ni vector, h.\(\vec{C} = 2 \vec{A} \times \vec{B}\), i.\(\vec{C} = \frac{\vec{A}}{B}\), j.\(\vec{C} = \frac{\vec{A}}{B}\)

    23. Wao ni orthogonal.

    Matatizo

    25. \(\vec{h}\)= -16.4 m\(\hat{u}\), 16.4 m

    27. 30.8 m, 35.7° magharibi ya kaskazini

    29. 134 km, 80°

    31. 7.34 km, 63.5° kusini mwa mashariki

    33. 3.8 km mashariki, 3.2 km kaskazini, 7.0 km

    35. 14.3 km, 65°

    37. a.\(\vec{A}\) = + 8.66\(\hat{i}\) + 5.00\(\hat{j}\)

    b.\(\vec{B}\) = + 3.01\(\hat{i}\) + 3.99\(\hat{j}\)

    c.\(\vec{C}\) = + 6.00\(\hat{i}\) - 10.39\(\hat{j}\)

    d.\(\vec{D}\) = -15.97\(\hat{i}\) + 12.04\(\hat{j}\)

    f.\(\vec{F}\) = -17.32\(\hat{i}\) - 10.00\(\hat{j}\)

    Mfumo wa kuratibu x y una x chanya kwa haki na chanya y up. Vector A ina ukubwa 10.0 na inaonyesha digrii 30 kinyume na mwelekeo mzuri wa x. Vector B ina ukubwa 5.0 na pointi 53 digrii kinyume na mwelekeo chanya x. Vector C ina ukubwa 12.0 na inaonyesha digrii 60 saa moja kwa moja kutoka mwelekeo mzuri x. Vector D ina ukubwa 20.0 na inaonyesha digrii 37 saa moja kwa moja kutoka mwelekeo hasi x. Vector F ina ukubwa wa 20.0 na inaonyesha digrii 30 kinyume na mwelekeo wa x hasi.

    39. a. 1.94 km, 7.24 km

    b. ushahidi

    41. 3.8 km mashariki, 3.2 km kaskazini, 2.0 km,\(\vec{D}\) = (3.8\(\hat{i}\) + 3.2\(\hat{j}\)) km

    43. P 1 (2.165 m, 1.250 m), P 2 (-1.900 m, 3.290 m), 5.27 m

    45. 8.60 m, A (2\(\sqrt{5}\) m, 0.647\(\pi\)), B (3\(\sqrt{2}\) m, 0.75\(\pi\))

    47. a.\(\vec{A} + \vec{B}\) = -4\(\hat{i}\) - 6\(\hat{j}\), |\(\vec{A} + \vec{B}\) | = 7.211,\(\theta\) = 236.3°

    b.\(\vec{A} -\vec{B}\) = -2\(\hat{i}\) + 2\(\hat{j}\), |\(\vec{A} - \vec{B}\) | = 2\(\sqrt{2}\),\(\theta\) = 135°

    49. a.\(\vec{C}\) = (\(\hat{i}\)5.0 -\(\hat{j}\) 1.0 - 3.0\(\hat{k}\)) m, C = 5.92 m

    b.\(\vec{D}\) = (4.0\(\hat{i}\) - 11.0\(\hat{j}\) + 15.0\(\hat{k}\)) m, D = 19.03 m

    51. \(\vec{D}\)= (3.3\(\hat{i}\) -6.6\(\hat{j}\)) km,\(\hat{i}\) ni upande wa mashariki, kilomita 7.34, -63.5°

    53. a.\(\vec{R}\) = -1.35\(\hat{i}\) - 22.04\(\hat{j}\)

    b.\(\vec{R}\) = -17.98\(\hat{i}\) + 0.89\(\hat{j}\)

    55. \(\vec{D}\)= (200\(\hat{i}\) + 300\(\hat{j}\)) yd, D = 360.5 yd, 56.3° kaskazini mwa mashariki; Majibu ya namba yangebaki sawa lakini kitengo cha kimwili kitakuwa mita. Maana ya kimwili na umbali itakuwa sawa kwa sababu 1 yd inalinganishwa na m 1.

    57. \(\vec{R}\)= —3\(\hat{i}\) - 16\(\hat{j}\)

    59. \(\vec{E}\)= E\(\hat{E}\), E x = + 178.9 V/m, E y = -357.8 V/m, E z = 0.0 V/m,\(\theta_{E}\) = -tan -1 (2)

    61. a.\(\vec{R}_{B}\) = (12.278\(\hat{i}\) + 7.089\(\hat{j}\) + 2.500\(\hat{k}\)) km,\(\vec{R}_{D}\) = (-0.262\(\hat{i}\) + 3.000\(\hat{k}\)) km

    b. |\(\vec{R}_{B} − \vec{R}_{D}\) | = 14.414 km

    63. a. 8.66

    b. 10.39

    c. 0.866

    d. 17.32

    65. \(\theta_{i}\)= 64.12°,\(\theta_{j}\) = 150.79°,\(\theta_{k}\) = 77.39°

    67. a. -119.98\(\hat{k}\)

    b. 0\(\hat{k}\)

    c. +93.69\(\hat{k}\)

    d. -240.0\(\hat{k}\)

    e. +3.993\(\hat{k}\)

    f. -3.009\(\hat{k}\)

    g. +14.99\(\hat{k}\)

    h. 0

    69. a. 0

    b. 173,194

    c. +199,993\(\hat{k}\)

    Matatizo ya ziada

    71. a. 18.4 km na 26.2 km

    b. 31.5 km na kilomita 5.56

    73. a. (r,\(\phi + \frac{\pi}{2}\))

    b. (2r,\(\phi + 2 \pi\))

    c. (3r, -\(\phi\))

    75. d PM = 33.12 nmi = 61.34 km, d NP = 35.47 nmi = 65.69 km

    77. ushahidi

    79. a. 10.00 m

    b. 5\(\pi\) m, c. 0

    81. 22.2 km/h, 35.8° kusini mwa magharibi

    83. 240.2 m, 2.2° kusini ya magharibi

    85. \(\vec{B}\)= -4.0\(\hat{i}\) + 3.0\(\hat{j}\) au\(\vec{B}\) = 4.0\(\hat{i}\) - 3.0\(\hat{j}\)

    87. ushahidi

    Changamoto Matatizo

    89. G \(\perp\)= 2375\(\sqrt{17}\) ≈ 9792

    91. ushahidi

    Wachangiaji na Majina

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