14.10: Equações-chave

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K _w = [H ₃ O ⁺] [OH ⁻] = 1,0

$\times$ 10 ⁻¹⁴ (a 25 °C)

$pH = −registro [H_{3} O^{+}]$

pOH = −log [OH ⁻]

[H ₃ O ⁺] = 10 ^−pH

[OH ⁻] = 10 ^−pOH

pH + pOH = p K _w = 14,00 a 25 °C

$K_{uma} = \frac{[H_{3} O^{+}] [{UMA}^{−}]}{[HA]}$

$K_{b} = \frac{[{HB}^{+}] [{OH}^{−}]}{[B]}$

Eu _sou

$\times$ K _b = 1,0

$\times$ 10 ⁻¹⁴ = K _w

$Porcentagem de ionização = \frac{{[H_{3} O^{+}]}_{eq}}{{[HA]}_{0}} \times 100$

p K _a = −log K _a

p K _b = −log K _b

$pH = p K_{uma} + tora \frac{[{UMA}^{−}]}{[HA]}$